Hi, I am facing difficulty in plotting these functions.
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
k=1;
x=[0:0.5:24];
y1= k*sin(pi*(x-12.9677)/14.8646);
y1(y1 < 0) = 0;
y2= k*sin(pi*(x-16.0495)/12.7009);
y2(y2 < 0) = 0;
y=y1+y2;
plot(x,y1);
hold on
plot(x,y2);
I want to plot y1 and y2 such that after 24 at the x coordinate, y1 and y2 arrive from 0 at x coordinate and the value of y1 at 24 , i.e. y1(24) = y1(0) and the the y curve must follow its original course as it would have followed after 24 but from 0 till the termination on the x-axis.
Here, based on my code (wrong), y1 is not showing up again from 0 till termination point and y2 is showing up but starting at a lower value from 0.
Also please keep in mind that i further wan sum of y1 and y2 in the 0 to 24 range.
0 to 24 is the time of day.
Thanks for reading. we
2 Kommentare
Enez Furkan Cihan
am 19 Jul. 2019
Bearbeitet: Enez Furkan Cihan
am 19 Jul. 2019
I'd try out to expand x axis by 'axis' command to make the figure's axis bigger than your plot's width.
Antworten (1)
Steven Lord
am 19 Jul. 2019
I want to plot y1 and y2 such that after 24 at the x coordinate, y1 and y2 arrive from 0 at x coordinate and the value of y1 at 24 , i.e. y1(24) = y1(0)
In that case you're going to need to change your y1 function. y1(0) will be equal (approximately) at x = 2*14.8646.
>> k = 1;
>> y1 = @(x) k*sin(pi*(x-12.9677)/14.8646);
>> y1([0 24])
ans =
-0.3903 0.7243
>> y1([0 2*14.8646])
ans =
-0.3903 -0.3903
Similarly for y2, with x = 2*12.7009:
>> k = 1;
>> y2 = @(x) k*sin(pi*(x-16.0495)/12.7009);
>> y2([0 24])
ans =
0.7368 0.9227
>> y2([0 2*12.7009])
ans =
0.7368 0.7368
0 Kommentare
Siehe auch
Kategorien
Mehr zu Annotations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!