How can I solve a nonlinear model using Newton Raphson ?
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    Mallouli Marwa
 am 15 Jul. 2019
  
    
    
    
    
    Kommentiert: Mallouli Marwa
 am 25 Jan. 2020
            Hi
How can I solve this nonlinear model using Newton Raphson ?
x1 +x2^2 +cos (x3) = 2
x1 +sin (x2) + x3^3 = 1
x3 +x2^3+x3^3 = 4
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  Stephan
      
      
 am 25 Jan. 2020
        One way:
result = fsolve(@fun,[1 1 1])
function F = fun(x)
F(1) = x(1) + x(2).^2 + cos(x(3)) - 2;
F(2) = x(1) + sin(x(2)) + x(3).^3 - 1;
F(3) = x(3) +x(2).^3 + x(3).^3 - 4;
end
gives:
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
result =
   -0.5583    1.3732    0.8329
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