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same input output signal name in simulink

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TaeHee Kwun
TaeHee Kwun am 12 Jul. 2019
Kommentiert: sreedevi am 13 Jun. 2021
I want to make code below by model (or stateflow) using Code Generation
if( var > 10){
var = 10;
}
In this case, upper 'var' is input of chart(or subsystem) and lower 'var' is output of chart.
So, it occurs signal complication if I use same variables name or I can't make same name of chart's input and output.
I can make this if sentance by using two variables, but I hope to make this by using one.
Thanks for your help.
Sincerely,
TaeHee Kwun.

Akzeptierte Antwort

Phani Teja
Phani Teja am 16 Jul. 2019
Bearbeitet: Phani Teja am 16 Jul. 2019
Yeh It can be possible with Data store memory block.
Make a Variable 'Var' in stateflow and change its scope to Data store memory .
You can also control the variable storage class by resolving data store memory with simulink signal.
The generated code looks like:
/* Real-time model */
RT_MODEL_Chart_T Chart_M_;
RT_MODEL_Chart_T *const Chart_M = &Chart_M_;
/* Model step function */
void Chart_step(void)
{
/* Chart: '<Root>/Chart' */
/* Re-use inputs */
if (Var > 10) {
/* NEW_PATTERN */
Var = 10;
}
/* End of Chart: '<Root>/Chart' */
}
  2 Kommentare
TaeHee Kwun
TaeHee Kwun am 20 Jul. 2019
Thanks for your answer!
But, I can't still understand how to make this blocks...
If you can, can you upload some of your blocks?
Thanks.
sreedevi
sreedevi am 13 Jun. 2021
Hi ,Did you get an answer for the question.If yes please post it

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