For loop error: Subscript indices must either be real positive integers or logicals

1 Ansicht (letzte 30 Tage)
I am executing a for loop but it gives following error at time 0.6:
T_o=[0;0;0];
T_d=[0;0;0];
T_l=[0;0;0];
out_n=zeros([],3);
for t=0:0.1:10
T_o = [0.05*(10-t);0.04*(10-t);0.03*(10-t)];
T_e=T_d-T_o;
T_e=[t*10 T_e'];
a = sim('PD_control','SimulationMode','normal');
out = a.get('T_u');
out_n(t*10+1,:) = out(2,:)
end
The Simulink file called by this code is attached here.

Akzeptierte Antwort

KSSV
KSSV am 12 Jul. 2019
T_o=[0;0;0];
T_d=[0;0;0];
T_l=[0;0;0];
out_n=zeros([],3);
tt=0:0.1:10 ;
for i = 1:length(tt)
t = tt(i) ;
T_o = [0.05*(10-t);0.04*(10-t);0.03*(10-t)];
T_e=T_d-T_o;
T_e=[t*10 T_e'];
a = sim('PD_control','SimulationMode','normal');
out = a.get('T_u');
out_n(i,:) = out(2,:)
end

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 12 Jul. 2019
mat2str((find((0:0.1:10)*10-(0:100))-1)/10)
0.3 0.6 0.7 1.2 1.4 2.3 2.4 2.8 2.9 4.1 4.6 4.8 5.2 5.4 5.9 6.2
That is, 0.3 * 10 is not 3.0 exactly.
0.1 in binary floating point is not exactly 1/10, just the same way that in decimal 0.333...3 * 3 is 0.999...9 instead of 1

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Produkte


Version

R2016a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by