Randomly select an element from a vector satisfying a condition

3 Ansichten (letzte 30 Tage)
Dear experts,
I would like to randomly select an element from a vector satisfying a condition. In fact, I want to know what is the fastest way. For example, suppose vector X defined as follows:
X = [1 2 3 4 5 2 3 6 7 8 8 7 9 10 0 1 2 3 8 5 6 4];
How should I randomly select and identify the index of an element in this vector, which is greater than 2?
Thanks for your help,
Amir

Akzeptierte Antwort

Amirhossein Moosavi
Amirhossein Moosavi am 1 Jul. 2019
I already have an answer to this question as follow (but I am seeking for faster solutions):
Ind = find(X > 2); Ind = Ind(randsample(1:numel(Ind), 1));
  2 Kommentare
Bruno Luong
Bruno Luong am 2 Jul. 2019
The solution seems fine and pretty optimal to me. If you insist on faster move away from MATLAB or buy a faster computer.
Arjun Siva S
Arjun Siva S am 7 Dez. 2020
Thanks a lot! I've been thinking about the same problem for a long time.

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Weitere Antworten (2)

Jos (10584)
Jos (10584) am 1 Jul. 2019
This is a two-step process:
  1. create an intermediate array with all elements of X satisfying your condition
  2. select a single element from that
You can combine the two steps in a single command:
randsample(X(X>2), 1)
  1 Kommentar
Amirhossein Moosavi
Amirhossein Moosavi am 1 Jul. 2019
Thanks for your time. This only gives the value of an element; while I want its index.

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David Goodmanson
David Goodmanson am 2 Jul. 2019
Relative speeds are going to depend on the length of X and the value N that the elements have to be greater than, (2 in the example). The following is generally faster, by a factor of 2 or so.
f = find(X > M); % M = 2
Ind = f(randi(length(f)));
  3 Kommentare
David Goodmanson
David Goodmanson am 2 Jul. 2019
I agree, although the question did specify a single draw.
Amirhossein Moosavi
Amirhossein Moosavi am 2 Jul. 2019
You are right. Many thanks for your attention.

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