Removing Rows from Character Vector?

The character vector Materials is a single column, 40 row vector with the names of the necessary materials.

The numeric vector Inventory is a single column, 40 row vector with the amount of each material in stock.

The numeric vector Needed is a single column, 40 row vector with the amount of each material we require.

The numeric vector Defecit is a single column, 40 row vector with the amount of each material we lack.

In order to parse down the final product to show just the rows of materials that we need to order, I wrote the following bit of code

DF = all (Deficit > 0 , length(Deficit)) %DF is a column vector the same length as Deficit that has a 1 if we need to order, a 0 if we do not.
DefecitFinal = Defecit(DF,:) %Similar code for the other numeric vectors to provide just the rows that we need to order
MaterialsFinal = Materials(DF,:) %Provides an error message

I feel like theres a really simple way that i'm just not familiar with to adjust the Materials data as well.

[KALYAN ACHARJYA]

Please explain the question in simple maths way, not as per your subjects.

What you have?

What result you are expecting?

[Justin Alexander]

There’s a column of materials.

There’s a column of 0’s and 1’s.

I need only the materials next to 1’s.

Answer 1

[Matt J]

Works fine for me,

Materials=["Iron";"Steel";"Wood";"Cheese"]; 
DF=logical([1 0 0 1].');

>> MaterialsFinal = Materials(DF)

MaterialsFinal = 

  2×1 string array

    "Iron"
    "Cheese"

[Justin Alexander]

I’ll give it another go then trying that once I get back. Thanks for the heads up.

UPDATE:

So i don't have DF as a logic array which is causing the problem. I'll try getting it as one brb.

SOLVED:

Yup, inserting the line

DF=logial(DF) ;

sovled the issue! Thanks!