if statement with sub cases
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Mohammed Qahosh
am 16 Jun. 2019
Bearbeitet: per isakson
am 20 Jun. 2019
I need to use the if statement in my code and I appreciate your help. I need it in the code like this:
I need to check the length of some thing, I have 3 cases but to of them have also 2 subcases as follows:
I have tow cases for L=17 and 2 cases for L==16 How can I manage that in the code ?
Thank you in advance for your help.
%%
A=regexp(text,'Time');
B=regexp(text,'Height');
L= B-A(1);
if L==17
C=strfind(text,'Time');
time_hour=str2num(text(C(1)+7:strfind(text,'Height')-9));
time_min=str2num(text(C(1)+10:strfind(text,'Height')-6));
time_sec=str2num(text(C(1)+13:strfind(text,'Height')-3));
time=60*60*time_hour + 60*time_min + time_sec;
elseif L==17
C=strfind(text,'Time');
time_hour=str2num(text(C(1)+7:strfind(text,'Height')-8));
time_min=str2num(text(C(1)+10:strfind(text,'Height')-6));
time_sec=str2num(text(C(1)+12:strfind(text,'Height')-3));
time=60*60*time_hour + 60*time_min + time_sec;
elseif L==15
C=strfind(text,'Time');
time_hour=str2num(text(C(1)+7:strfind(text,'Height')-7));
time_min=str2num(text(C(1)+10:strfind(text,'Height')-5));
time_sec=str2num(text(C(1)+12:strfind(text,'Height')-3));
time=60*60*time_hour + 60*time_min + time_sec;
elseif L==16;
C=strfind(text,'Time');
time_hour=str2num(text(C(1)+7:strfind(text,'Height')-8));
time_min=str2num(text(C(1)+10:strfind(text,'Height')-5));
time_sec=str2num(text(C(1)+13:strfind(text,'Height')-3));
time=60*60*time_hour + 60*time_min + time_sec;
elseif L==16
C=strfind(text,'Time');
time_hour=str2num(text(C(1)+7:strfind(text,'Height')-8));
time_min=str2num(text(C(1)+10:strfind(text,'Height')-6));
time_sec=str2num(text(C(1)+12:strfind(text,'Height')-3));
time=60*60*time_hour + 60*time_min + time_sec;
end
2 Kommentare
per isakson
am 16 Jun. 2019
Bearbeitet: per isakson
am 16 Jun. 2019
"I have two cases for L=17 and 2 cases for L==16" How do the two cases differ? I don't want to figure that out by backward engineering your script.
I believe that the task can be solved by a few lines of code, either with sscanf() or better use of regexp(). If such a solution would be helpful, please provide a handful of examples of the text that shall be parsed.
Akzeptierte Antwort
per isakson
am 16 Jun. 2019
Bearbeitet: per isakson
am 20 Jun. 2019
Try
%%
text = 'Time = 16:0:16 Height';
%%
num = sscanf( text, 'Time = %d:%d:%d Height' );
time = [ 60*60, 60, 1 ] * num;
added in response to comment
%%
text = 'Time = 16:0:16 Height';
%%
num = sscanf( text, 'Time = %d:%d:%d Height' );
t1 = [ 60*60, 60, 1 ] * reshape( num, [],1 );
%%
cac = regexp( text, '(?<=Time = )(\d+):(\d+):(\d+)(?= Height)', 'tokens' );
t2 = [ 60*60, 60, 1 ] * reshape( str2double(cac{1}), [],1 );
%%
t1==t2
outputs
ans =
logical
1
In response to request in separate answer
Run
>> tic, S = read_pco_header( 'h:\m\cssm\pco.txt' ); toc
Elapsed time is 0.011812 seconds.
and peek on the result
>> S
S =
struct with fields:
FileName: "D:\experiment\MoleculeExp\FEM\Video\v190322ad\v190322ad_0.pco"
File_version: "1"
Date: "22.3.2019"
Time: 54745
Height: 600
Width: 800
Binning: 1
Exposure_Time: 1000
Average: 5
Temperature: 45
Pixel_Rate: 12
Tip_Voltage: 2100
Shutter_State: 0
>>
and
>> S.Time
ans =
54745
>>
where
function S = read_pco_header( filespec )
%{
S = read_pco_header( 'h:\m\cssm\pco.txt' );
%}
S = struct( ...
'FileName' , {[]} ...
, 'File_version' , {[]} ...
, 'Date' , {[]} ...
, 'Time' , {[]} ...
, 'Height' , {[]} ...
, 'Width' , {[]} ...
, 'Binning' , {[]} ...
, 'Exposure_Time' , {[]} ...
, 'Average' , {[]} ...
, 'Temperature' , {[]} ...
, 'Pixel_Rate' , {[]} ...
, 'Tip_Voltage' , {[]} ...
, 'Shutter_State' , {[]} ...
);
fid = fopen( filespec, 'rt' );
chr = fscanf( fid, '%c' , 2048 );
fclose( fid );
string_array = string( strsplit( chr, '\n' ) );
for str = string_array
tokens = split( str, ["=",":"] );
key = strtok( tokens(1) );
switch key
case "PCO"
% do nothing
case "FileName"
% The separator, ":", between name and value ...
S.FileName = strtrim(tokens(2)+":"+tokens(3));
case "File_version"
S.File_version = strtrim(tokens(2));
case "Date"
S.Date = strtrim(tokens(2));
case "Time"
S.Time = [3600,60,1]*reshape( str2double(tokens([2,3,4])), [],1 );
case "Height"
S.Height = str2double(tokens(2));
case "Width"
S.Width = str2double(tokens(2));
case "Binning"
S.Binning = str2double(tokens(2));
case {"Exposure","Exposure_Time"}
S.Exposure_Time = str2double(strtok(tokens(2)));
case "Average"
S.Average = str2double(tokens(2));
case "Temperature"
S.Temperature = str2double(tokens(2));
case {"Pixel","Pixel_Rate"}
S.Pixel_Rate = str2double(tokens(2));
case {"Tip","Tip_Voltage"}
S.Tip_Voltage = str2double(tokens(2));
case {"Shutter","Shutter_State"}
S.Shutter_State = str2double(tokens(2));
case "End"
% do nothing
case ""
% do nothing
otherwise
error( 'read_pco_header:UnknownKey' ...
, 'Unexpected key, "%s", in "%s%"' ...
, key, filespec )
end
end
end
Afterthought
I uploaded a somewhat improved version of read_pco_header
and here is a version of the "regexp-script" that works with the test file
%%
ffs = 'h:\m\cssm\pco.txt';
fid = fopen( ffs, 'rt' );
chr = fscanf( fid, '%c' , 2048 );
fclose( fid );
cac = regexp( chr, '(?<=Time = )(\d+):(\d+):(\d+)\s+Height', 'tokens' );
t2 = [ 60*60, 60, 1 ] * reshape( str2double(cac{1}), [],1 );
%%
It feels like overkill to include "Height" in the regular expression. However, it's included in the original question.
14 Kommentare
per isakson
am 17 Jun. 2019
I'm glad if it's useful and will be used.
I uploaded a somewhat improved version of read_pco_header
Weitere Antworten (1)
Siehe auch
Kategorien
Mehr zu String Parsing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!