Problem in integration in an array inside integrand

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Anil Kumar
Anil Kumar am 8 Jun. 2019
Kommentiert: Star Strider am 10 Jun. 2019
I am getting the error named "Attempted to access R(2); index out of bounds because numel(R)=1." in the below code. can anyone help me? below is my code.
Nd = 1e24;
N = 100;
e = 12*1e-12;
% R = [10e-9,20e-9,30e-9,40e-9];
R = [1e-9,2e-9,3e-9,4e-9]
Et_Ef = -1.01*1.6*1e-19;
K = 1.3807e-23;
T = linspace(450,600,N);
Nt = linspace(1e14,1e17,N);
q = 1.6e-19;
Ld = 1.97*10e-9
for j = 1:numel(R)
for i= 1:N
funct = @(R,phi0) (4*pi*(Nd-Nd*exp(-phi0))*R.^2);
equation = @(phi0)integral(@(R)funct(R,phi0),0,R(j))-(4*pi*R(j)^2*Nt(i)/(1+2*exp((Et_Ef + K.*T(i) .*(phi0 + (1/6)*(R(j)/Ld)^2))./(K.*T(i)))));
%equation = @(phi0)integral(@(r)funct(r,phi0),0,R)-(4*pi*R^2*Nt(i)/(1+2*exp((Et_Ef + K*T *(phi0 + (1/6)*(R/Ld)^2))/(K*T))));
phi0val(j,i) = fzero(equation,40);
funneff= @(R)1./(4/3.*pi.*R(j).^3).*(Nd.*exp(-phi0val(j,i))).*R(j).^2
neff(j,i)= (1./(4./3.*pi.*R(j).^3)).*4.*pi.*integral(funneff,0,R(j),'Arrayvalued',true)
end
end
plot(neff(1,:),phi0val(1,:))
plot(neff(2,:),phi0val(2,:))
plot(neff(2,:),phi0val(2,:))
plot(neff(2,:),phi0val(2,:))

Akzeptierte Antwort

Star Strider
Star Strider am 8 Jun. 2019
Bearbeitet: Star Strider am 8 Jun. 2019
You are using ‘R’ in too many contexts. It is a vector, however it is also an argument to your anonymous functions, and anonymous functions pick up variables from the workspace. Changing the anonymous functions argument ‘R’ to ‘Rv’ allows your code to run:
neff = zeros(numel(R),N);
phi0val = zeros(numel(R),N);
for j = 1:numel(R)
for i= 1:N
funct = @(Rv,phi0) (4*pi*(Nd-Nd*exp(-phi0))*Rv.^2);
equation = @(phi0)integral(@(Rv)funct(Rv,phi0),0,R(j))-(4*pi*R(j)^2*Nt(i)/(1+2*exp((Et_Ef + K.*T(i) .*(phi0 + (1/6)*(R(j)/Ld)^2))./(K.*T(i)))));
%equation = @(phi0)integral(@(r)funct(r,phi0),0,R)-(4*pi*R^2*Nt(i)/(1+2*exp((Et_Ef + K*T *(phi0 + (1/6)*(R/Ld)^2))/(K*T))));
phi0val(j,i) = fzero(equation,40);
funneff= @(Rv)1./(4/3.*pi.*Rv.^3).*(Nd.*exp(-phi0val(j,i))).*Rv.^2;
neff(j,i)= (1./(4./3.*pi.*R(j).^3)).*4.*pi.*integral(funneff,0,R(j),'Arrayvalued',true);
end
end
figure
hold all
for k = 1:size(neff,1)
plot(neff(k,:),phi0val(k,:))
end
hold off
expstr = @(x) [x(:).*10.^ceil(-log10(abs(x(:)))) floor(log10(abs(x(:))))];
Rexp = expstr(R)
hl = legend(sprintfc('$R\\ =\\ %2d\\times10^{%d}$',Rexp));
hl.Interpreter = 'latex';
Check to be certain this does what you want to to do.
The Plot —
Problem in integration in an array inside integrand - 2019 06 08.png
EDIT — Added plot image.
  2 Kommentare
Anil Kumar
Anil Kumar am 10 Jun. 2019
Nicely explained ! thank you sir!
Star Strider
Star Strider am 10 Jun. 2019
As always, my pleasure!

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