Filter löschen
Filter löschen

Result producing 1x5 array instead of 10x5?

4 Ansichten (letzte 30 Tage)
Thomas Veith
Thomas Veith am 4 Jun. 2019
Kommentiert: Alex Mcaulley am 4 Jun. 2019
Hi all,
I have the following code which I'm expecting to produce a 10x5 array but it's only giving me a 1x5, and I'm not sure why?
n = 10;
result = zeros(n,5);
for k=1:n;
A0=1;P0=29;g=rand;p=rand;B=rand;
result = [A0,P0,g,p,B];
end;
Alternatively, if I write the code this way I get a 10x1 cellular array, each entry of which represents a 1x5 numeric array. This gives me the number of results I want, but not in the format I'm looking for (which, again, is ultimately a 10x5 array). Thanks in advance!
n = 10;
result = cell(n,1);
for k=1:n;
A0=1;P0=29;g=rand;p=rand;B=rand;
result{k} = {A0,P0,g,p,B};
end;

Akzeptierte Antwort

Alex Mcaulley
Alex Mcaulley am 4 Jun. 2019
You need to specify the index:
n = 10;
result = zeros(n,5);
for k=1:n;
A0=1;P0=29;g=rand;p=rand;B=rand;
result(k,:) = [A0,P0,g,p,B];
end;
  4 Kommentare
madhan ravi
madhan ravi am 4 Jun. 2019

That would just copy the same g p B values through repmat() so creating n elements for g p B and then copying it into the matrix would be better.

Alex Mcaulley
Alex Mcaulley am 4 Jun. 2019
Yes, as @madhan said, if you want random numbers for all rows:
n = 10;
A0=1;P0=29;
result = [repmat([A0,P0],n,1),rand(n,3)]

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Rob L
Rob L am 4 Jun. 2019
Your first method overwites the result every loop with a [ 1 x 5 ] array.
You could (among many other solutions) use:
n = 10;
result = zeros(n,5);
for k=1:n
A0=1;P0=29;g=rand;p=rand;B=rand;
result(k,1) = A0;
result(k,2) = P0;
result(k,3) = g;
result(k,4) = p;
result(k,5) = B;
end

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by