Check to find if a row has an element occuring more than once

I need to find if a row has more than one occurence of 1s. I am expecting a response return like true or false. Sample row matrix is below:

0 0 1 1 0 0

Answer 1

[Stephan]

A = [0 0 1 1 0 0; 0 0 0 0 0 1; 1 1 0 0 0 1]
res = (sum(A==1,2)>1)

This works row-wise for more than 1 rows

[altaf ahmed]

thanks Stephan

res = (sum(A==1,2)>1)

1 is the element to be matched in that row but what is 2 in the above line.

[madhan ravi]

doc sum % read it

[altaf ahmed]

Followup question:

Once the non-zero elements of a row are identified, how can we increment all non-zero elemnts only by one. e.g.

a = [0 0 1 1 0 0]

becomes a = [0 0 2 2 0 0]

same operartion needs to be repeated in all rows.

[madhan ravi]

idx = a~=0;
a(idx) = a(idx) + 1;