calculation of a mean matrix

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Hi I have two matrices
a = [1 2 3; 2 3 4]
and
b = [2 3 4; 3 4 5];
I want a mean output matrix "c," whose output should be
c= [1.5 2.5 3.5; 2.5 3.5 4.5].
so basically "c" should have a mean of respective parameters and same dimension as "a" and "b". Can someone help?
Thanks, Subrat
  1 Comment
Yanbo
Yanbo on 15 Aug 2012
you might just simply add a to b, and them divide the sum by 2. Or, are you looking for a specific command?

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Accepted Answer

Oleg Komarov
Oleg Komarov on 15 Aug 2012
Unfortunately your example doesn't allow to propose a unique solution, i.e.:
c1 = [mean(a); mean(b)]
c2 = squeeze(mean(cat(3,a,b),3));
c1 simply takes the vertical mean (along rows) of a and then concatenates the vertical mean of b
c2 takes the mean of row 1 from a AND b and then concatenates the mean of the second row fro the two matrices.
Which one do you want?
  2 Comments
Subrat kumar sahoo
Subrat kumar sahoo on 15 Aug 2012
I have a bit different requirement now: if "a" and "b" happens to be two elements of the same cell like d{1} and d{2} then is there a possibility of getting "c2" (*c2 = squeeze(mean(cat(3,a,b),3));*) with elements "a" and "b" (i.e. now d{1} and d{2}) picked thru a "for" loop? Thanks, Subrat

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More Answers (3)

Image Analyst
Image Analyst on 15 Aug 2012
a = [1 2 3; 2 3 4];
b = [2 3 4; 3 4 5];
c = (a+b)/2
In the command window:
c =
1.5 2.5 3.5
2.5 3.5 4.5
  1 Comment
Oleg Komarov
Oleg Komarov on 15 Aug 2012
This is the so much more intuitive version of my c2!

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Thomas
Thomas on 15 Aug 2012
Edited: Thomas on 15 Aug 2012
a = [1 2 3; 2 3 4];
b = [2 3 4; 3 4 5];
c=[mean(a);mean(b)]

Benjamin Klugah-Brown
Benjamin Klugah-Brown on 9 Aug 2020
what if matrix a and b have different size
  5 Comments
Walter Roberson
Walter Roberson on 10 Aug 2020
If by NA you mean NaN, then you would have to use
mean(cat(3, A1, B1), 3, 'omitnan')
or you would have to use something like
maskA = isnan(A1);
maskB = isnan(B1);
C1 = (A1 + B1) / 2;
C1(maskA) = B1(maskA);
C1(maskB) = A1(maskB);

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