Array indices must be positive integers or logical values.
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
hey, im new in matlab.
I have attached the original question and my solution is written below:
clc; clear;
%t = linspace(0,2,100);
t= (0:0.05:2);
V=12;
R=4;
L=1.3;
g= zeros(1,length(t));
for j=t
if j<=0.5
g(j)=((V\R)*(1-(exp((-R*j)\L))));
else
g(j)=(exp((-R*j)\L)*(V\R)*(exp((0.5*R)\L)-1));
end
end

0 Kommentare
Antworten (1)
KSSV
am 3 Mai 2019
Bearbeitet: KSSV
am 3 Mai 2019
Note that the index of array cannot be zero, negative and fraction...so the error.
%t = linspace(0,2,100);
t= (0:0.05:2);
V=12;
R=4;
L=1.3;
g= zeros(1,length(t));
for j=1:length(t)
if t(j)<=0.5
g(j)=((V\R)*(1-(exp((-R*j)\L))));
else
g(j)=(exp((-R*j)\L)*(V\R)*(exp((0.5*R)\L)-1));
end
end
2 Kommentare
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!