Evaluating integral numerically using quadgk
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Hi
I am trying to evaluate the following integral numerically in MatLAB: http://www.scribd.com/doc/100400549/mwe
However, the sqrt(x^2 + y^2) in the numerator has changed to x. Here is my attempt (based on this thread: http://mathworks.com/matlabcentral/answers/43929-evaluate-advanced-integral-numerically#answer_53917):
clc
clear all
myquad = @(fun,a,b,tol,trace,varargin)quadgk(@(x)fun(x,varargin{:}),a,b,'AbsTol',tol);
sigma = 1;
kappa = 1e4;
B = 1e6;
beta = 1.0;
f = 1e6;
fct = @(x,y,z,f) (...
(x)/sqrt(x.^2+y.^2+z.^2)).*(exp((-x.^2-y.^2-z.^2)/(2*sigma^2)))./ ((f - B*beta*sqrt(x.^2+y.^2+z.^2)).^2 + kappa^2/4 );
result = triplequad(@(x,y,z) fct(x,y,z,f), -Inf, Inf, -Inf, Inf, -Inf, Inf, 1e-16, myquad);
However this gives me a warning: "Rank deficient, rank = 0, tol = NaN.". I'm not sure what else to do here. Am I using triplequad correctly?
Best wishes, Niles.
2 Kommentare
Niles Martinsen
am 14 Aug. 2012
Teja Muppirala
am 14 Aug. 2012
If that changes to an x, then the integral is zero by symmetry.
Antworten (1)
Mike Hosea
am 14 Aug. 2012
0 Stimmen
Make sure that you are using elementwise operations. See the first / in fct? It should be ./ instead. Check all the other multiplications and divisions. If it's only a scalar multiplication or division, then you don't need to change it, but in fact I find it easier just to use all .* and ./ rather than * or /.
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