how to compare two arrays

A=[
9.9090    8.3211  9.5763
9.7926    8.2055  9.4335
9.3428    7.7533  8.8443]

COMPARED TO

B=[
7.9   9.5    9.5
8.7   10.3   10.3
9.5   11.1   11.1
10.3  11.9   11.9
11.1  12.7   12.7
11.9  14.3   14.3]

i need code that compares each row of A with each row of B

choosing the very next value from B for each element in A

elaboration:-

first element in A is 9.9090 comparing it to first row in B

7.9 is less so rejected

8.7 is less so rejected

9.5 is less so rejected

10.3 is more so acceped

result= 
10.3   9.5  10.3
10.3   9.5  9.5
9.5    9.5  9.5

Answer 1

[dpb]

O=zeros(size(A));
for i=1:size(A,2)
  O(:,i)=interp1(B(:,i),B(:,i),A(:,i),'next','extrap');
 end

[Omar Almahallawy]

is there a way i can have all the columns nex to each other other than iterations

O=

10.3

10.3

9.5

O=

9.5

9.5

9.5

O=

10.3

9.5

9.5

can i change it to be like this

O=

10.3 9.5 10.3

10.3 9.5 9.5

9.5 9.5 9.5

[dpb]

Just store into array by column...see updated Answer. (Figured that obvious, sorry...)