Matrix indexing collecting accurate results
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Nikolaos Zafirakis
am 30 Apr. 2019
Kommentiert: KSSV
am 30 Apr. 2019
I have a for loop and some challenging mathematical equations my goal is to get a 3x3 matrix where A is preferable I would like to make A1 A2 cell matrices and collect the values leading to an easy final equation. Thanks in advance for anyone that helps me out!
for i = 1:100;
v2(1:3,i) = [cross(v1(1:3,i),(Sb(1:3,i)))/norm(cross(v1(1:3,i),(Sb(1:3,i))))]; % Works 3x1
w2(1:3,i) = [cross(w1(1:3,i),(Bb(1:3,i)))/norm(cross(w1(1:3,i),(Bb(1:3,i))))]; % Works 3x1
v3(1:3,i) = cross(v1(1:3,i),v2(1:3,i)); % Works 3x1
w3(1:3,i) = cross(w1(1:3,i),w2(1:3,i)); % Works 3x1
A1 = transpose([v1(1:3,i),v2(1:3,i),v3(1:3,i)]); % Works but donsn't store values 3x3
A2 = [w1(1:3,i),w2(1:3,i),w3(1:3,i)]; % Works but donsn't store values 3x3
A = mtimes(A1,A2); % Not working 3x3
end
0 Kommentare
Akzeptierte Antwort
KSSV
am 30 Apr. 2019
Bearbeitet: KSSV
am 30 Apr. 2019
A1 = zeros(3,3,100) ;
A2 = zeros(3,3,100) ;
A = zeros(3,3,100) ;
for i = 1:100;
v2(1:3,i) = [cross(v1(1:3,i),(Sb(1:3,i)))/norm(cross(v1(1:3,i),(Sb(1:3,i))))]; % Works 3x1
w2(1:3,i) = [cross(w1(1:3,i),(Bb(1:3,i)))/norm(cross(w1(1:3,i),(Bb(1:3,i))))]; % Works 3x1
v3(1:3,i) = cross(v1(1:3,i),v2(1:3,i)); % Works 3x1
w3(1:3,i) = cross(w1(1:3,i),w2(1:3,i)); % Works 3x1
A1(:,:,i) = transpose([v1(1:3,i),v2(1:3,i),v3(1:3,i)]); % Works but donsn't store values 3x3
A2(:,:,i) = [w1(1:3,i),w2(1:3,i),w3(1:3,i)]; % Works but donsn't store values 3x3
A(:,:,i) = mtimes(A1,A2); % Not working 3x3
end
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!