how to replace 'NaN' values with any other values in a cell array
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SOUVIK DATTA
am 29 Apr. 2019
Kommentiert: Rik
am 30 Apr. 2019
in this cell, how can i replace nan value?
for i=1:8
if ~isempty(d11{i})
for ix= 1:length(d11{i})
for j=1:length(d11{i}{ix})
for w=1:length(d11{i}{ix}{j})
for k=1:length(d11{i}{ix}{j}{w})
% if isnan(d11{i}{ix}{j}{w}(k))
% d11{i}{ix}{j}{1}(k)=.000001;
% end
d11{i}{ix}{j}{w}(k)(cellfun(@isnan,d11{3}{1}{1}{2}(k)))={'0'}
end
end
end
end
end
end
output: Error: ()-indexing must appear last in an index expression.
2 Kommentare
Rik
am 29 Apr. 2019
You are using parentheses twice. How deep is your cell array? 4 or 5 levels deep? And why isn't your commented code working?
Also, are you sure you want to assign a char array to your cell instead of a normal 0 (of type double)?
Akzeptierte Antwort
Walter Roberson
am 30 Apr. 2019
d11 = fixnan(d11);
function x = fixnan(x)
%will work no matter how many levels, including if cells are not consistent types
if isnumeric(x)
x(isnan(x)) = 0;
elseif iscell(x)
x = cellfun(@fixnan, x, 'uniform', 0);
%else other types do nothing, return unchanged
end
end
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