Creating Timetables: Error Message in SampleRate
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FW
am 18 Apr. 2019
Kommentiert: Peter Perkins
am 3 Mai 2019
Hello, I am trying to use a suggested function to generate a timetable with a sampling frequency of 200 Hz.
tt = timetable(rand(12,1),'SampleRate', 200)
I get an error: Invalid parameter name: SampleRate. This is MATLAB 2017b.
How do we get the desired sample rate?
Thanks.
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Adam Danz
am 18 Apr. 2019
Bearbeitet: Adam Danz
am 19 Apr. 2019
Here's a link to the 2017b documentation for timetable().
Here's how to achive your example for releases before and after 2018b.
% 2018b or more recent
data = rand(12,1);
sampleRate = 200; %hz
tt = timetable(data,'SampleRate', sampleRate);
% prior to 2018b
timeSamples = seconds(0 : 1/sampleRate : (size(data)-1)/sampleRate);
tt = timetable(timeSamples', data);
2 Kommentare
Peter Perkins
am 3 Mai 2019
Adam is right, but usually this
seconds((0:(size(data)-1))/sampleRate)
is better numerically.
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