How to divide the value of different matrix dimensions

i am transmitting data in Rayleigh channel for one receiving antenna i.e Nr = 1; so, earlier my code is running fine but i want to increase the no. of receiving antenna i.e for Nr =2. but when i am doing this the value of H is earlier is of dimension (1x1 double complex) and received signal is (1x390) complex double. For nullify the effect of channel fading i have divided the received signal with H. . But for Nr =2, the dimension of channel parameter becomes 2x1 double complex i.e (H =[0.916914643137897 + 0.609000311025438i} ; 0.153860641195036 - 0.516117945123273i] and received signal becomes to 2 x 390 double complex. Now when i am dividing the signal with H, i am getting error.As the matrix dimensions mismatch. . i dont understand how to do it.

% Received Signal = Faded Signal + AWGN Noise.

r = faded_r + AWGN;

r =r./H

Answer 1

[Walter Roberson]

You appear to be using R2016a or earlier. In R2016b or later, dividing a 2 x 390 by a 2 x 1 is valid.

In R2016a and earlier, use bsxfun:

bsxfun(@divide, signal, H)

[rayna kumari]

Yes, i am using R2015a. It is showing me this error.

bsxfun Undefined function 'divide' for input arguments of type 'double'.

[Walter Roberson]

Sorry, should be @rdivide not @divide