Signal plot - Can't figure out error

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STP
STP am 2 Apr. 2019
Kommentiert: KSSV am 2 Apr. 2019
t1= [0 5];
t2a = [5 6];
t2b = [6 7];
t3 = [7 10];
Eo1 = exp(1i*pi);
phi = 2*pi/3; % any angle as its the slope
k = -phi/(t2a(1)-t1(1));
Eo2a = @(t)exp(1i*(phi + k*(t-t1(1))));
Eo2b = exp(1i*0);
Eo3 = 0;
t= [t1; t2a; t2b; t3];
Eo = [Eo1; Eo2a(t2a); Eo2b; Eo3];
%% this should be the figure below.
plot(t, real(Eo), 'DisplayName','Real')
plot(t, imag(Eo), 'DisplayName','Im')
legend
What am I doing wrong? -- as I don't get the below plot Eo as outcome
  5 Kommentare
Walter Roberson
Walter Roberson am 2 Apr. 2019
You define k in terms of t2a(1) and t1(1) . That implies you think t1 and t2a are vectors.
You define Eo1 as a scalar constant.
You define Eo2a as a function handle, and pass the vector t2a to it, getting back a vector of results. It might be a row vector rather than a column vector. When you try to use [A;B] between a scalar and a row vector, that is not going to work.
STP
STP am 2 Apr. 2019
Bearbeitet: STP am 2 Apr. 2019
I edited as per your comments - but still no output
t1= [0 5];
t2a = [5 6];
t2b = [6 7];
t3 = [7 10];
Eo1 = exp(1i*pi);
phi = 2*pi/3; % any angle as its the slope
k = -phi/(t2a(1)-t1(1));
Eo2a = @(t)exp(1i*(phi + k*(t-t1(1))));
Eo2b = exp(1i*2*pi);
Eo3 = 0;
t= [t1; t2a; t2b; t3];
Eo = [Eo1; Eo2a; Eo2b; Eo3];
%% this should be the figure below.
plot(t, real(Eo), 'DisplayName','Real')
plot(t, imag(Eo), 'DisplayName','Im')
legend
It is basically this that would give out the plot shown above-
Capture.JPG

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Antworten (1)

KSSV
KSSV am 2 Apr. 2019
Eo2a is a function handle...you have to input t and get output. You should run something like below. REthink on your code.
t1= [0 5];
t2a = [5 6];
t2b = [6 7];
t3 = [7 10];
Eo1 = exp(1i*pi);
phi = 2*pi/3; % any angle as its the slope
k = -phi/(t2a(1)-t1(1));
Eo2a = @(t)exp(1i*(phi + k*(t-t1(1))));
Eo2b = exp(1i*2*pi);
Eo3 = 0;
t= [t1; t2a; t2b; t3];
Eo = [Eo1 Eo2a(t1) Eo2b ];
%% this should be the figure below.
plot(t, real(Eo), 'DisplayName','Real')
plot(t, imag(Eo), 'DisplayName','Im')
legend
  2 Kommentare
STP
STP am 2 Apr. 2019
Bearbeitet: STP am 2 Apr. 2019
Hi, KSSV; thanks for your input - I tried this way too- but I still don't get this output (Eo)
KSSV
KSSV am 2 Apr. 2019
I have only solved the error.....didn't work on the real problem.

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