how can I keep the user to input a value that is devisable by 7
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hello,
I think the answer to this is very simple. the code that I am trying to do is to keep asking for a number that is divisable by 7. once the user enters a number that is div by 7, the code ends. I got the part where the user input is div by 7 and ends, but I cant find a way to keep asking for input if the number is not div by 7. here is what I got.
usernum = input('enter a posative number: ');
i = 1;
deviby7 = rem(usernum, 7);
while i > 0
if deviby7 ~= 0
fprintf('incorrect input\n')
elseif deviby7 == 0
fprintf('correct input\n')
i = i -1;
end
end
Antworten (1)
madhan ravi
am 31 Mär. 2019
while 1
usernum = input('enter a positive number: ');
deviby7 = rem(usernum, 7);
if ~deviby7
fprintf('correct input\n')
break
else
fprintf('incorrect input\n')
end
end
3 Kommentare
Stephen23
am 31 Mär. 2019
Nice and simple. Here also without the temporary variable:
while true
usernum = input('enter a positive number: ');
if rem(usernum, 7)
fprintf('incorrect input\n')
else
fprintf('correct input\n')
break
end
end
madhan ravi
am 31 Mär. 2019
Very true, thank you Stephen.
madhan ravi
am 31 Mär. 2019
If you had run the code you won’t be asking this question.
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