Getting values from 4d matrix according (using) 2d matrix with logical values (0 or 1) - does not work as wanted
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    Yurii Iotov
 am 29 Mär. 2019
  
    
    
    
    
    Bearbeitet: Linus Olofsson
 am 24 Jun. 2020
            Hello!
Let say I have a matrix A of dimensions (50*100*248*20) with data and I have another one  B (50*100) with logical values (lets image I have 100 of  "1") and I want to get values from my 4D matrix according to B. So I am doing 
C = A(B);
But then I am getting my values only from A (:,:,1,1) - first page, but I am expecting to get values from all the pages (along all the 3rd and 4 th dimensions). How can I do this?
So I need at the output a matrix with dimensions (100, 1, 248, 20) - which give me 100 values from each page of 248*20
If I am not clear, let me know!, Hoping for you help! Thanks!
6 Kommentare
  madhan ravi
      
      
 am 4 Apr. 2019
				
      Bearbeitet: madhan ravi
      
      
 am 4 Apr. 2019
  
			Indeed sir Walter, thank you for the explanation just noticed the comment.
  Linus Olofsson
 am 24 Jun. 2020
				
      Bearbeitet: Linus Olofsson
 am 24 Jun. 2020
  
			Could someone please give an example of the explanation Walter gave above? I do not really understand how this is a solution of the problem, nor do I understand the code snippet provided by the earlier comment by Walter.
Could the solution please be explained with my very similar non-functional problem with a 3 channel color image and a 2 dimensional logical array (mask) that I would like to use to color code speficic parts of my image, i.e.:
image = zeros(150,5370,3);
whos mask
  Name              Size               Bytes  Class      Attributes
  mask            150x5370            805500  logical
image(mask,2) = 255; % Change the masked part of the image to be green.
Akzeptierte Antwort
  Yurii Iotov
 am 29 Mär. 2019
        3 Kommentare
  Walter Roberson
      
      
 am 29 Mär. 2019
				I think you mean that Zeros are only to be removed at the edges.
The code I posted here finds the bounding box that contains all of the 1's. It could easily be extended to more dimensions.
Weitere Antworten (1)
  Darren Wethington
 am 29 Mär. 2019
        See if this is what you're looking for:
A = rand(10,20,30,40);
B = round(rand(10,20));
four_dim_logical = zeros(size(A));
for i=1:length(four_dim_logical(1,1,:,1))
    for j=1:length(four_dim_logical(1,1,1,:))
        four_dim_logical(:,:,i,j) = B;
    end
end
C = A(logical(four_dim_logical));
dim1 = sum(B(:));
dim2 = 1;
dim3 = size(A,3);
dim4 = size(A,4);
C = reshape(C,dim1,dim2,dim3,dim4);
2 Kommentare
  Darren Wethington
 am 29 Mär. 2019
				Just saw solutions in the comments.  This solution will be MUCH more computationally expensive if either of those work.
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