If else If statment embedded in a for loop with a constraint?

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Clifford Shelton
Clifford Shelton am 3 Aug. 2012
It's not easy being a beginner!
Ok..I'm trying to add some bias to the following random walk in values. Here's the example code:
for i=1:20;
% Let j = probability for specific value
% Let k = the probability that two adjacent values will be equal
j =rand;
k =rand;
if 0<=k<=.0063
value(i+1)=value(i);
elseif 0<=j<=.0687
value(i+1)=0;
elseif .0688<=j<=.1880
valuei+1)=1;
elseif .1881<=j<=.3286
value(i+1)=2;
How would I add a constraint (or bias) the above random walk so that every 10 adjacent values (of the 20 random values that will be generated by the above code) must maintain a moving average with the value of 1?
I hope i'm clear on what I'm trying to do. Thanks for all the help in advance!
  3 Kommentare
Clifford Shelton
Clifford Shelton am 3 Aug. 2012
Ok. The for loop will create 20 random numbers. I want every 10 adjacent numbers together to have an average equal to 1. Example: I want {(i(1)+i(2)+i(3)+i(4)....)/10=1}
So i'm trying to create a constraint (or bias) within the random number generation.
I hope that is clearer. Sorry for the confusion
Oleg Komarov
Oleg Komarov am 3 Aug. 2012
I posted some code on your duplicate question where you already received lots of feedback: http://www.mathworks.co.uk/matlabcentral/answers/45204-adding-a-constraint-to-my-if-else-if-statement
The moving average condition comes out now.
Please, formulate the condition concisely and clearly in your old post before duplicating it.

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Antworten (1)

Sven
Sven am 3 Aug. 2012
Bearbeitet: Sven am 3 Aug. 2012
Hi Clifford, Your description (from the comments above) will only happen if the second 10 numbers are an exact copy of the first 10 numbers. Think of it this way:
Imagine your first 10 random numbers add up to 10. Numbers 2:11 have simply dropped the first number and added the 11th number. If the sum of these must also add up to 10, this will only happen if i(11)==i(1), and then i(12)==i(2) for the next set, etc.
That being said, here's how I would do it:
% Make the first 10 random numbers
randSet = rand(10,1);
% Force them (by scaling) to add up to 10
randSet = randSet * (10/sum(randSet));
% Turn them into 20 numbers (by copying, as per my description above)
finalRandSet = [randSet; randSet];
% See that all windows of 10 adjacent numbers equal 10
sum(finalRandSet(1:10))
sum(finalRandSet(5:14))
sum(finalRandSet(9:18))
Did this help you out Clifford?
  6 Kommentare
Clifford Shelton
Clifford Shelton am 3 Aug. 2012
Ok...that is a better way to look at what I'm trying to do. Thanks. But now i'm a little confused as to how can I after forcing the rows to add up to 40 (by scaling) then set a probabilities (or bias) for specific values that could be created "randomly".
so in other words:
for example, I want to populate a 5-by-10 matrix.
I want the average of each row of 10 numbers to equal 4.
AND I want a 10% probability that the first value is 1
a 5% probability that the first vale is 2
a 15% probability that the first value is 3
a 10% probability that the first value is 4 etc...etc...
This way I want to generate a program that can solve the problm of generating values for my matrix with strict bias of 1. having each group of 10 averaging to 4 and 2. populating the list with biased probabilities.
Thanks for all your help!!
Sven
Sven am 4 Aug. 2012
Hi Clifford....
I'm getting a bit dizzy here watching those goalposts shift with every post...
Perhaps you should update your question with the code you have up to now and describe clearly what your (working) code does, and how it doesn't yet meet your needs.

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