using 2 indexs for loop

3 Ansichten (letzte 30 Tage)
Morten Jørgensen
Morten Jørgensen am 21 Mär. 2019
Kommentiert: Morten Jørgensen am 22 Mär. 2019
Hi
how can i optimize this loop, if i want to include another indexing
mHome is an 15001x28 array
mBall is an 15001x3 array
for i=1:length(mHome)
output1(i,1)=pdist([mHome(i,1:2);mBall(i,1:2)]);
output1(i,2)=pdist([mHome(i,3:4);mBall(i,1:2)]);
output1(i,3)=pdist([mHome(i,5:6);mBall(i,1:2)]);
output1(i,4)=pdist([mHome(i,7:8);mBall(i,1:2)]);
output1(i,5)=pdist([mHome(i,9:10);mBall(i,1:2)]);
output1(i,6)=pdist([mHome(i,11:12);mBall(i,1:2)]);
output1(i,7)=pdist([mHome(i,13:14);mBall(i,1:2)]);
output1(i,8)=pdist([mHome(i,15:16);mBall(i,1:2)]);
output1(i,9)=pdist([mHome(i,17:18);mBall(i,1:2)]);
output1(i,10)=pdist([mHome(i,19:20);mBall(i,1:2)]);
output1(i,11)=pdist([mHome(i,21:22);mBall(i,1:2)]);
output1(i,12)=pdist([mHome(i,23:24);mBall(i,1:2)]);
output1(i,13)=pdist([mHome(i,25:26);mBall(i,1:2)]);
output1(i,14)=pdist([mHome(i,27:28);mBall(i,1:2)]);
end
% I have tried this but it does not work
for i=1:length(mHome)
for k=1:size(mHome,2)
output1(i,k)=pdist([mHome(i,k);mBall(i,1:2)]);
end
end
  3 Kommentare
madhan ravi
madhan ravi am 21 Mär. 2019
Even after the below?
for k=1:size(mHome,2)
output1(k,1)=pdist([mHome(k,(k*2)-1:k*2);mBall(k,1:2)]);
end
What the size of mBall?
Morten Jørgensen
Morten Jørgensen am 21 Mär. 2019
mBall is a 15001x3 array.
but im only using the first 2 columms
my output should be a 15001x14 array

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Thorsten
Thorsten am 21 Mär. 2019
for i=1:length(mHome)
for k=1:2:size(mHome,2)-1
output1(i,k)=pdist([mHome(i,k:k+1);mBall(i,1:2)]);
end
end
  1 Kommentar
Morten Jørgensen
Morten Jørgensen am 22 Mär. 2019
many thanks.
the only problem is that the output is a 15001x27 array and it should be a 15001x27 array.
right now everyother column is a colum with 0

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by