Data must be numeric, datetime, duration or an array convertible to double.
    3 Ansichten (letzte 30 Tage)
  
       Ältere Kommentare anzeigen
    
    Akshay Pratap Singh
 am 15 Mär. 2019
  
    
    
    
    
    Kommentiert: Akshay Pratap Singh
 am 15 Mär. 2019
            I wrote a following code. It shows error:"Data must be numeric, datetime, duration or an array convertible to double."
clear all
clc
syms x
h=4;
q=0; 
delta=26;
phi=39;
kh=0;
kv=0;
psi=atan(kh/(1-kv));
da1=delta*(pi/180);  pha1=phi*(pi/180);
m=pha1+da1;
b=pha1-psi;
c=psi+da1;
gma=18.4;   nq=2*q/(gma*(x));
delta=26;
phi=39;
lam=0;
A=lam*nq/(1+nq);
alphac=atan((sin(m)*sin(b)+(sin(m)^2+sin(b)^2+sin(m)*cos(m)*sin(b)*cos(b)+A*cos(c)*cos(m)*sin(b))^0.5)/(A*cos(c)+sin(m)*cos(b)));
w=0.5*gma*(x)^2*(1/tan(alphac));
B=(x)*((1/tan(alphac))-lam);
ka1=((1+nq)*(1-A*tan(alphac))*(cos(b)-(sin(b)/tan(alphac))))/(cos(psi)*(cos(m)+tan(alphac)*sin(m)))
pa1=0.5*gma*x^2*ka1
x=0:0.1:5;
plot(pa1,x)
Akzeptierte Antwort
  madhan ravi
      
      
 am 15 Mär. 2019
        syms x
h=4;
q=0; 
delta=26;
phi=39;
kh = 0;
kv=0;
s=...; % didn't define s
psi = atan (kh / (1-kv));
da1 = delta * (pi / 180); pha1 = phi * (pi / 180);
m=pha1+da1;
b=pha1-psi;
c=psi+da1;
gma = 18.4;
nq = 2 * q / (gma * (x));
delta=26;
phi=39;
lam = 0;
leg=...; % didn't define leg
Null=...;
A = lam * s / (1 + Null);
    %   ^---only one
alphac = atan ((sin (m) * sin (b) +...
    (sin (m) ^ 2 + sin (b) ^ 2 +...
    sin (m) * cos (m) * sin (b) * cos (b) +...
    A * cos (c) * cos (m) * sin (b) ^ 0.5) / (A * cos (c) +...
    sin (m) * cos (b))));
w=0.5*gma*(x)^2*(1/tan(alphac));
B = (x) * ((1 / tan (alphac)) - lam);
ka1 = ((1 + nq) * (1-A * tan (alphac)) *...
    (cos (b) - (sin (b) / tan (alphac))))...
    * (cos (psi) * (leg*(m ) + tan (alphac) * sin (m)))
                    %  ^---- missed it
pa1 = matlabFunction(0.5 * gma * x ^ 2 * ka1);
x=0:0.1:5;
plot(pa1(x),x)
Weitere Antworten (0)
Siehe auch
Kategorien
				Mehr zu Numbers and Precision finden Sie in Help Center und File Exchange
			
	Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
