Filter löschen
Filter löschen

plot 1st order bessel derivative

5 Ansichten (letzte 30 Tage)
zamri
zamri am 31 Jul. 2012
Kommentiert: Md Rezaul Karim am 19 Apr. 2020
Hi all,
Can i ask if somebody can help me on why i got 'matrix dimension don't agree' thereby cannot get a plot for first order bessel derivative.
If i type 'diff(besselj(1,z),z)', i'd get 'besselj(0, z) - besselj(1, z)/z'
but then when i want to plot 'besselj(0, z) - besselj(1, z)/z' by typing:
format long
z = (0:1:100)';
a=besselj(0, z) - besselj(1, z)/z;
plot(z,a)
it'd give error as below:
??? Error using ==> minus
Matrix dimensions must agree.
Error in ==> Untitled at 4
a=besselj(0, z) - besselj(1, z)/z;
for some reason the second term gives 101x101 dimension which doesnt agree with the first term (101x1).

Akzeptierte Antwort

Matt Kindig
Matt Kindig am 31 Jul. 2012
I think you need to use element-wise division with the z:
a=besselj(0, z) - besselj(1, z)./z;

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 31 Jul. 2012
besselj(1, z)/z is using the mrdivide operator ("/"), and so is the least-squares solution to X*z = besselj(1, z) . This will not be a vector.
If you want to construct the list of [besselj(1,K) / K] for K in 0 : 100, then you should use the rdivide arithmetic divide operator rather than the matrix divide operator:
besselj(1, z) ./ z
  1 Kommentar
zamri
zamri am 1 Aug. 2012
thanks Walter, u're brilliant.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Bessel functions finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by