create a new matrix from
v = [1 1 1 2 2 2 3 3 4];
u=unique(v);
R=arrayfun(@(x)v==u(x),1:numel(u),'un',0);
M=+vertcat(R{:})
what if my matrix is
newV = [1; 1; 1; 2; 2; 2; 3; 3; 4];
what is the change i need to make without transposing the vector newv, to get the output M with newV
i used horzcat, but still without transposing, i'm not able to get result as M

3 Kommentare

madhan ravi
madhan ravi am 13 Mär. 2019
Why do you think transpose() should not be used?
Elysi Cochin
Elysi Cochin am 13 Mär. 2019
My data was in that form, so, i was asking if i could do it directly.
KSSV
KSSV am 13 Mär. 2019
It works with newV also....you need not to change any part of code.

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 Akzeptierte Antwort

madhan ravi
madhan ravi am 13 Mär. 2019

1 Stimme

R=arrayfun(@(x)reshape(newV,1,[])==u(x),1:numel(u),'un',0);

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