Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
can not plot the graph and there is samething wrong on my script, can anyone checkit
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
clear all
clc
t = [-5:50]
for n =1:length(t)
if (n>=-5&&n<=0);
y1=zeros;
elseif (n>=0&&n<=8) ;
y2=10*n.^2-5*n;
elseif (n>=8&&n<=16);
y3=624-5*n;
elseif (n>=16&&n<=26);
y4=36*n+12*(n-16)^2;
else (n>=26&&n<=50);
y5=2136*exp(-0.1*(n-26));
end
end
figure(1)
plot(n,y1,n,y2,n,y3,n,y4,n,y5)
xlabel('time');ylabel('v(t)')
0 Kommentare
Antworten (2)
Rik
am 9 Mär. 2019
Your code doesn't do what you think it does. You could see that by looking at your variables: they have become scalars, instead of vectors.
What you should do is take advantage of the array processing you can do with Matlab (with logical indexing), or use indexing in your loop.
t = [-5:50]
y = NaN(size(t))
L= t>=-5 & t<=0;
y(L)=0;
L=t>=0 & n<=8;
y(L)=10*t(L).^2-5*t(L);
L=t>=8 & t<=16;
y(L)=624-5*t(L);
L=t>=16 & t<=26;
y(L)=36*t(L)+12*(t(L)-16)^2;
L=t>=26 & t<=50;
y(L)=2136*exp(-0.1*(t(L)-26));
figure(1)
plot(t,y)
xlabel('time');ylabel('v(t)')
3 Kommentare
Star Strider
am 9 Mär. 2019
@arham zakki edelo — Rik’s code uses ‘logical indexing’, the most efficient way to do this problem.
If you want to continue with your for loop and if block, try this:
t = -5:50;
for n =1:length(t)
if (t(n)>=-5&t(n)<=0);
y1(n)=zeros;
t1(n) = t(n);
elseif (t(n)>=0&t(n)<=8);
y2(n)=10*n.^2-5*t(n);
t2(n) = t(n);
elseif (t(n)>=8&t(n)<=16);
y3(n)=624-5*t(n);
t3(n) = t(n);
elseif (t(n)>=16&t(n)<=26);
y4(n)=36*n+12*(t(n)-16)^2;
t4(n) = t(n);
else (t(n)>=26&t(n)<=50);
y5(n)=2136*exp(-0.1*(t(n)-26));
t5(n) = t(n);
end
end
figure(1)
plot(t1,y1, t2(t2>0),y2(t2>0), t3(t3>0),y3(t3>0), t4(t4>0),y4(t4>0), t5(t5>0),y5(t5>0))
xlabel('time')
ylabel('v(t)')
Then go back and un-accept the Comment that you accepted as an Answer, and accept Rik’s Answer that actually provided you with working code.
Experiment to get the result you want.
Praveen Kumar Pakkirisamy
am 9 Mär. 2019
What was your question and what are you trying to do? It is not quite clear from your Code
2 Kommentare
Rik
am 9 Mär. 2019
This is not an answer, but a comment. Please delete this and repost as a comment.
Diese Frage ist geschlossen.
Siehe auch
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!