Hello everyone.
Please I need help in automatically dividing the matrix A below into three 5by 1 matrix.
A=[1
2
3
4
5
6
8
9
10
11
12
13
14
15]
Such that the first matrix created will be say
B=[1
2
3
4
5]
Thanks.

 Akzeptierte Antwort

Akira Agata
Akira Agata am 7 Mär. 2019

1 Stimme

How about the following?
In this case, C{1}, C{2}, ..., C{151} are 200-by-1 matrices each, extracted from original 30194-by-1 matrix.
% Sample 30194-by-1 data
A = rand(30194,1);
% Padding with "nan"
n = 200;
N = numel(A);
A = [A;nan(ceil(N/n)*n-N,1)];
% Divide A into 200-by-1 segments
C = mat2cell(A,repelem(n,ceil(N/n)));

2 Kommentare

madhan ravi
madhan ravi am 7 Mär. 2019
reshape() is much faster
Benedict Egbon
Benedict Egbon am 7 Mär. 2019
Hi Akira.
Thanks for the respone.
This actually worked well for me as desired.
Regards.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Kevin Phung
Kevin Phung am 7 Mär. 2019

1 Stimme

A = reshape(1:15,5,3); %reshaped into a 5x3 matrix.
B =A(:,1); %one of the column vectors that you desire
reading up on indexing can help:

1 Kommentar

Benedict Egbon
Benedict Egbon am 7 Mär. 2019
Thank you very much for the response as this worked very well for this case.
At the moment, I have a 30194 by 1 matrix, and I want to make many 200 by 1 matrices from it.
Any suggestion on how to automate it, instead of doing B =A(:,1), C =A(:,2) etc.
Thanks.

Melden Sie sich an, um zu kommentieren.

Kategorien

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by