Write this without a for loop?

for c= delaySamples+1:length(audioVec)
EchoVec(c)=audioVec(c)+z(c-(delaySamples)*EchoGain);
end

4 Kommentare

Andrei Bobrov
Andrei Bobrov am 3 Mär. 2019
Bearbeitet: Andrei Bobrov am 3 Mär. 2019
What is z, EchoGain?
Michelle
Michelle am 3 Mär. 2019
heres the entire code for my function
function EchoVec=soundEcho(audioVec,Fs,delay,EchoGain)
EchoGain=input('enter how loud echo should be:');
delay=input('enter in a delay value in seconds:');
delaySamples=Fs*delay;
z=[zeros(1,delaySamples),audioVec'];
audioVec(length(delaySamples))=0;
for c= delaySamples+1:length(audioVec)
EchoVec(c)=audioVec(c)+z(c-(delaySamples)*EchoGain);
end
sound(EchoVec,Fs);
end
madhan ravi
madhan ravi am 3 Mär. 2019
Bearbeitet: madhan ravi am 3 Mär. 2019
when a third person runs your code (it is not possible to run) , nobody has the power to know what is in your computer
Walter Roberson
Walter Roberson am 15 Nov. 2020
Michelle, if you feel that the question is unclear, then as you are the person who posted the question, you should be the one who clarifies it to make it more clear.

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Antworten (1)

Alex Mcaulley
Alex Mcaulley am 4 Mär. 2019

0 Stimmen

If audioVec is a column array and you ensure that (delaySamples)*EchoGain is a valid index:
c = delaySamples+1:length(audioVec);
EchoVec(delaySamples+1:length(audioVec))=audioVec(delaySamples+1:end)+z(c-(delaySamples)*EchoGain);

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