How to get only one or two output times from ODE solver?
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
winkmal
am 21 Feb. 2019
Kommentiert: winkmal
am 25 Feb. 2019
I am programming a nonlinear optimization, during which an ODE is solved multiple times at each objective function call. So I would like to make this part as efficient as possible. What I have noticed is that it seems to be impossible to get only one, or only two values in time as output from the solver.
Take this ODE for example:
function dx = CstrConsecutiveReaction(t, x, params)
k_1 = params(1);
k_2 = params(2);
k_3 = params(3);
k_4 = params(4);
q_in = params(5);
V_liq = params(6);
A_in = params(7);
B_in = params(8);
C_in = params(9);
D_in = params(10);
A = x(1);
B = x(2);
C = x(3);
D = x(4);
% RHS of ODE system
dx(1,1) = -k_1*A + q_in/V_liq*(A_in - A);
dx(2,1) = 2*k_1*A - 2*k_2*B*B + 2*k_3*C - k_4*B + q_in/V_liq*(B_in - B);
dx(3,1) = k_2*B*B - k_3*C + q_in/V_liq*(C_in - C);
dx(4,1) = k_4*B + q_in/V_liq*(D_in - D);
end
If I call it like this:
x0 = [1.5, 0.1, 0, 0];
params = [1.0, 1.5, 0.75, 0.15, 3, 15, 0.5, 0, 0, 0];
[t_sol, x_sol] = ode15s(@(t, x) CstrConsecutiveReaction(t, x, params), 0:1, x0)
I get 33x4 values! Why? If I use 0:0.5:1 as time vector, I get three.
I am only interested in the value at t=1, so ideally, I would like to get a 1x4 output from ode15s. Right now, I need to filter the values I need after each solver call, like this:
A = x_sol(end, 1);
D = x_sol(end, 4);
Any suggestions how I could improve this?
0 Kommentare
Akzeptierte Antwort
Torsten
am 21 Feb. 2019
Bearbeitet: Torsten
am 21 Feb. 2019
If you use two elements in tspan, ode15s returns the solution at intermediate output times chosen from its internal stepsize control. If you use more than two elements in tspan, ode15s returns the solution at these specified times. So, x_sol will at least be a 3x4 matrix.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Ordinary Differential Equations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!