In need of decreasing exponential smooth curve

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Abhinandana R
Abhinandana R am 10 Feb. 2019
Kommentiert: Abhinandana R am 10 Feb. 2019
u=0.3; pi=22/7; g=80;
l=20; d=10; p=1;
r=linspace(0,1,10);
m=tand(p)
a=(r-m*(d+l)).^-2-((r-m*l).^-2)
q=(pi*r.^4*g)/(8*u*l)
t=(2*u*q.*a)/(pi*m)
plot(r,t)
I need a decreasing smooth exponential curve. please help me

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Stephan
Stephan am 10 Feb. 2019
Bearbeitet: Stephan am 10 Feb. 2019
Your linspace call will lead to 10 results calculated in the interval of 0...1. If you leave the 10 away, the standard is 100 values, which gives a smoother curve:
u=0.3; g=80;
l=20; d=10; p=1;
r=linspace(0,1);
m=tan(p);
a=(r-m*(d+l)).^-2-((r-m*l).^-2);
q=(pi*r.^4*g)/(8*u*l);
t=(2*u*q.*a)/(pi*m);
plot(r,t)
You should also do not overwrite pi - it is a constant in Matlab - no need to define it.
Best regards
Stephan
  3 Kommentare
Stephan
Stephan am 10 Feb. 2019
Bearbeitet: Stephan am 10 Feb. 2019
what about
m=exp(p)
for the interval 0...1 it is a smooth decreasing curve. That is the desired result?
Abhinandana R
Abhinandana R am 10 Feb. 2019
yeah thanks !

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