convert character date string to date vector

Hello

I have a date character string in the following format "2014-07-03T04:00:00.000000Z" within a table structure. I wish to convert this to a format which I can plot on a graph axis using the plot function.

plot(x,y)

where x is the date and y is some time series of data.

How can i convert the current date format?

Answer 1

[YT]

You can use datetime to do it

myString = '2014-07-03T04:00:00.000000Z';
myDateString = datetime(myString,'InputFormat','yyyy-MM-dd''T''HH:mm:ss.SSS''Z','TimeZone','UTC');

dateOnly = myDateString; %create copy for dates
timeOnly = myDateString; %create copy for times

dateOnly.Format = 'dd-MM-yyyy'; %dates / x
timeOnly.Format = 'HH:mm:ss.SSS'; %times / y

or use regular expressions

D = regexp(input,'(?<date>.*?)T(?<time>.*?)Z','names');
%D.date = '2014-07-03'
%D.time = '04:00:00.000000';

[madhan ravi]

input() is an in-built function so naming a variable as input is not a good idea.

[YT]

ah thanks, changed it ;)