Filter löschen
Filter löschen

Can ode45 solve a ODE with space dependent parameters?

2 Ansichten (letzte 30 Tage)
Marlon Saveri Silva
Marlon Saveri Silva am 28 Jan. 2019
Kommentiert: James Tursa am 5 Aug. 2021
Hello,
I read ode45() can solve functions with time dependent parameters like this below by interpolating f and g during each time step.
y'(t)+f(t)y(t)=g(t)
However, can ode45 (or other solver) solve a system of odes like this below in which [A], [B] and [C] are matrices with some terms dependent of y and y=y(t)?
{dy/dt} = [A]{y^4}+[B]{y}+{C}
Ai=Ai(y)
Bi=Bi(y)
Ci=Ci(y)
Well, since this equation appears in a problem I solve using Simscape (Backward Euler method as default), I suppose I could find a solver to solve it inside Matlab codes without using Simscape.
  2 Kommentare
Jan
Jan am 29 Jan. 2019
The notation is not clear to me: "{dy/dt} = [A]{y^4}+[B]{y}+{C}"
Marlon Saveri Silva
Marlon Saveri Silva am 29 Jan. 2019
Bearbeitet: Marlon Saveri Silva am 29 Jan. 2019
Actually this is not a MATLAB command line notation, I tried this "mathematical notation" to emphasize y, dy/dt and C are vectors whereas A and B are matrices.
{y} = {y1, y2, y3, ... , yn}
{C} = {c1, c2, c3, ... , cn}
{dy/dt} = {y1', y2', y3', ... , yn'}
Moreover, by {y^4} I tried to indicate the vector is {y1^4, y2^4, y3^4, ... yn^4}.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

James Tursa
James Tursa am 29 Jan. 2019
Yes. In general, if the derivative is a function of current state and time (even if there are vectors or matrices involved), then you can use ode45 to get a numerical solution. The caveat is that the function needs to be "nice" enough for ode45 to handle. Otherwise you may need stiff solvers, etc.
  5 Kommentare
Ying Wu
Ying Wu am 5 Aug. 2021
Hi Silva, I have met the same problem, my ODE has parameter A which is the piecewise function of the first directive y'(t). Have you succeed in solving this problem?
James Tursa
James Tursa am 5 Aug. 2021
@Ying Wu It would be best if you posted a new Question with the details of your particular problem & derivative functions.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by