question using while loop

variable = input('Continue?', 's');
while variable == 'y'
    disp(rand)
    variable = input('Continue?', 's');  
    if (variable ~= 'y')
        return
    end
end

Need to write a code that if you type 'y', it displays a random variable. If the typed variable is not equal to 'y' then the program should terminate. When I run my code, it keeps displaying "continue?" no matter what variable I type. How would I get this to display a number? (needs to use a while loop)

Answer 1

[Stephen23]

v = input('Continue?', 's');
while strcmpi(v,'y')
    disp(rand)
    v = input('Continue?', 's');  
end

When applied to character vectors the equivalence operator == performs an element-wise comparison (as it does on all array types). To compare the complete character vector, use strcmp or strcmpi.