Can I get some help for this question?
Below is my attempt
x=[1 3 5 9 11 13];
y=[22 51 127 202 227 248 252];
scatter(x,y)
That is the furthest I can go. Any help would be appretiated. :)

4 Kommentare

Stephan
Stephan am 21 Jan. 2019
start with completing your x data - the seven is missing. Then begin to read about least squares curve fitting. To do this you should learn how to code your function in Matlab using a function handle.
Torsten
Torsten am 21 Jan. 2019
Bearbeitet: Torsten am 21 Jan. 2019
Hint:
log(C/H(t) - 1) = log(A) - B*t
This turns your problem into a linear regression problem.
Gulfstream Gaming
Gulfstream Gaming am 21 Jan. 2019
@Stephan, Thanks for pointing out the mistake, I just noticed it. Thanks for the links for me to read as well. Appreciate it a lot. See you around!
Gulfstream Gaming
Gulfstream Gaming am 22 Jan. 2019
@Torsten, thanks for the hint, will appreciate it a lot. :)
See you around

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 Akzeptierte Antwort

Star Strider
Star Strider am 21 Jan. 2019
Bearbeitet: Star Strider am 21 Jan. 2019

1 Stimme

I don’t know if you have the Optimization Toolbox or the Statistics and Machine Learning Toolbox, both of which have nonlinear regression functions. One function everyone has is fminsearch (link).
To use it, you will need to optimise a function of the form:
fcn = @(b) norm(y - Hfcn(b,t));
where ‘Hfcn’ is the function you will write for ‘H(t)’, ‘b’ is the parameter vector, and ‘t’ and ‘y’ are the respective data vectors.
I leave the rest to you!
EDIT —
Your ‘t’ vector is also missing a value. It should be:
t=[1 3 5 7 9 11 13];
I discovered that when I actually did the regression.

2 Kommentare

Gulfstream Gaming
Gulfstream Gaming am 21 Jan. 2019
@Star Strider, yup, i have both. Thanks for providing me the link. Appreciate it a lot. See you around! I like your profile photo
Star Strider
Star Strider am 21 Jan. 2019
As always, my pleasure.
My polar bear thanks you for the compliment!

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