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How to create a loop calcualtion?

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Kokalz am 19 Jul. 2012
Hi Guys! I am writing a GUI that processes some excel data and got to a point, where I need it to do some loop calculation. However, I have absolutely no idea how to do it. I tried going through all Doug's tutorials, but could not find anything, that would explain it. So here's the idea:
Say i need a 1x20 matrix. I know the first value of this vector, but all he other values come from the calculations that require the first value. So here's the sequence of the calculation:
Take the first value > input it into formulas with other variables > get the second value > use the second value to get the 3 rd value > get the 3rd value > use the 3rd value to get the 4th value > and so on.... Then plot all the acquired values on the graph against time.
Could someone help me out with it? Tell me if I made i too confusing..
Thank you, guys!
  1 Kommentar
Hi guys, can some one help me to solve my problem?
i've be facing difficulty to find the number of function evaluation. let's say that i have f(x)=x^3+x^2-2 with initial value of x(0)=1.5
i want to calculate x(n+1)=x(n)-(f(x(n)/fprime(x(n))) until n=5
thus, i want to calculate how many time of f(x(n)) have been use until n=5. but if the first iteration has use f(x(1)) then the second iteration also use f(x(1)), it is considered as we only use f(x(1)) one time only.
can someone help me

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Antworten (4)

Thomas am 19 Jul. 2012
Probably something like this..
num_values=10; % total values
output=zeros(1,num_values); %preallocate space for output
output(1)=first_val; % first value of output
for count=2:num_values
output(count)=output(count-1)+25; %formula current value depends on previous

Ryan am 19 Jul. 2012
So you have a 1 x 20 vector you want to fill off of knowing just the first value and each previously value determines the next? Is this what you're looking for:
t = 1:1:20; % for graphing later
x = zeros(1,20);
x(1) = .5; % Assign first value of "x"
for m = 2:numel(x)
x(m) = sin(x(m-1)); % Calculates the current cell "m" off of prior cell "m-1"

C.J. Harris
C.J. Harris am 19 Jul. 2012
Here is an example of a quick loop that calculates a value based on the previous value. The loop simply calculates the value as twice the previous value:
A = zeros(1,20); % Initialize array
A(1) = 1; % Set first value to 1
for nLoop = 2:length(A) % Start loop at second value
A(nLoop) = A(nLoop-1) * 2; % Answer is twice the previous value

Kokalz am 19 Jul. 2012
Thanks a lot fellas! I really don't know which question to mark up, as all of them seem to use the more or less same method, so I'l just upvote them!


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