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Traversing an image matrix columnwise

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Karan Ratnaparkhi
Karan Ratnaparkhi am 31 Mär. 2011
Hi guys i wanna traverse a matrix of an image column wise ie. it should consider first column and visit all the rows of that column and so on using for loops. Plz help me if u know the logic or code.

Akzeptierte Antwort

Josh
Josh am 31 Mär. 2011
If I understand your question, the solution is a nested for loop along the lines of
[rows,cols] = size(Matrix);
for col = 1:cols
for row = 1:rows
work with Matrix(row,col);
end
end
  2 Kommentare
MechtEngineer
MechtEngineer am 31 Mär. 2011
Exactly the same as mine above, except neater!
Karan Ratnaparkhi
Karan Ratnaparkhi am 31 Mär. 2011
thnx josh n mark..

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Weitere Antworten (2)

MechtEngineer
MechtEngineer am 31 Mär. 2011
I think you would want the following, assuming an m x n matrix A(row x column) with position of each array point (i,j)
for j = 1:size(A,2) % for each column
for i = 1:size(A,1) % for each row
% put your operation in here - I am just adding 1 to each pixel as an eg.
A(i,j) = A(i,j) + 1;
end
end

David Young
David Young am 31 Mär. 2011
Linear indexing uses columnwise ordering, so as long as you don't need the row and column indexes explicitly, you can do
for k = 1:numel(A)
% operate on A(k)
end
It might be even better to consider whether you can vectorise the operation and avoid the loops altogether.
  1 Kommentar
MechtEngineer
MechtEngineer am 31 Mär. 2011
Impressive solution! That really shortens the code required, and does the same thing.
And yes, as David Young says above, if you vectorise (or make the desired operations into matrices to add, subtract, multiply, correlate, etc) the operation, it will be quicker than "for" loops - I tried it recently, and my code ran 5 times faster!

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