Sequence of a specific number in a matrix
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Jonas Damsbo
am 3 Jan. 2019
Beantwortet: Star Strider
am 3 Jan. 2019
Hey
So my trouble is that I have a matrix, here a an example becuase my original matrix is really big.
0 1 1 1 0
0 1 0 1 1
1 1 0 0 0
1 1 1 0 1
0 1 1 1 1
Now I want the sequences of 1 in each row so I get something like:
3
1 2
2
3 1
4
It is possible?
0 Kommentare
Akzeptierte Antwort
Star Strider
am 3 Jan. 2019
Try this:
M = [ 0 1 1 1 0
0 1 0 1 1
1 1 0 0 0
1 1 1 0 1
0 1 1 1 1];
dM = diff([zeros(size(M(:,1))), M, zeros(size(M(:,1)))], 1, 2);
for k1 = 1:size(M,1)
first = strfind(dM(k1,:), 1);
last = strfind(dM(k1,:), -1);
dif{k1,:} = last - first;
end
cols = max(cellfun(@(x)size(x,2), dif));
Result = zeros(size(M,1),cols);
for k1 = 1:size(M,1)
Result(k1,1:numel(dif{k1})) = dif{k1};
end
producing
Result =
3 0
1 2
2 0
3 1
4 0
The actual output is in the ‘dif’ cell array. The code after that and the second loop simply converts it to a double array I call ‘Result’.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Resizing and Reshaping Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!