Hi everybody, I am using the following for loop code
for j = 3:1:6
A(j)=1*10.^(-j);
end
This gives me A=[0 0 0.001 0.0001 1e-05 1e-06]
I need the value of A for j = 3, 4, 5, and 6. In the above result my desired values are (0.001 0.0001 1e-05 1e-06). I don’t know from where the first 2 values (0 0) come, which are not required here. Any guidance will be appreciated thanks

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madhan ravi
madhan ravi am 31 Dez. 2018
Bearbeitet: madhan ravi am 31 Dez. 2018

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Reason: The first two elements are zero because you assign the values from index three so matlab assigns the first two values as zeros because matlab index starts from one.
You don't need loop at all:
A=10.^(-(3:6));
But if you insist one then:
n=3:6;
A=zeros(1,numel(n)); % preallocate
for j = 1:numel(n)
A(j)=10.^(-n(j));
end
A
Gives:
A=[ 0.001, 0.0001, 0.00001, 0.000001]

2 Kommentare

Safi ullah
Safi ullah am 31 Dez. 2018
In present case I need for loop your code works well @ madhan ravi thanks
madhan ravi
madhan ravi am 31 Dez. 2018
Anytime :)

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