if i have a y1 function of t , and y2 function of t and i want to plot convolution of y1 and y2 with time, how to do that it gives me length error

3 Kommentare

madhan ravi
madhan ravi am 20 Dez. 2018
share your code
t=0:0.1:10;
y1=3*t+5;
y2=4*t.^2+1;
output=conv(y1,y2);
plot (t,output)
vishal raj
vishal raj am 20 Nov. 2019
plot(output)

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madhan ravi
madhan ravi am 20 Dez. 2018
Bearbeitet: madhan ravi am 20 Dez. 2018

1 Stimme

syms t
y1=3*t+5;
y2=4*t^2+1;
fplot(y1*y2)
%edit after Brunos suggestion it’s not possible to represent the convolution for these functions

6 Kommentare

Mohamed H
Mohamed H am 20 Dez. 2018
Yess it worked, Thank youu
madhan ravi
madhan ravi am 20 Dez. 2018
Anytime :)
Bruno Luong
Bruno Luong am 20 Dez. 2018
Bearbeitet: Bruno Luong am 20 Dez. 2018
Careful, the solution provided by ravi is discrete convolution.
Your functions actually doesn't have finite (continuous) convolution, they are not integrable on any standard function space.
You change the t vector (length/step) you'll see the values of the discrete convolution is not stable.
So what is the result? I think it's mostly garbage.
madhan ravi
madhan ravi am 20 Dez. 2018
yes completely agree with Bruno , so how can it be plotted?
Bruno Luong
Bruno Luong am 20 Dez. 2018
It cannot be plotted. The convolution is not defined for those functions.
madhan ravi
madhan ravi am 20 Dez. 2018
Thanks Bruno for making it loud and clear.

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