To call a function results in an error (fzero)
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I am really new to matlab. When I wrote two functions like this:
funw.m
function q = funw(t)
h=0;
r=1/7;
q = quadl(@(x) sqrt(t^(2*r)-x.^(2*r)),h,t)...
-quadl (@(x) sqrt(x.^(2*r)-t^(2*r)),t,(h+2));
return
VentRate.m
function w = VentRate
global elev;
global h;
w = fzero(@funw,(h+elev)/2);
return
I try to use VentRate to call funw, by typing VentRate in the command window, but it will show some error. However, if i directly write w = fzero(@funw,(h+elev)/2) in the command window, it will run without error. So can anyone tell me what is wrong with the second function? I appreciate your help.
Error:
??? Error using ==> fzero at 422 Second argument must be a scalar or vector of length 2.
Error in ==> VentRate at 4 w = fzero(@funw,(h+elev)/2);
0 Kommentare
Akzeptierte Antwort
Thomas
am 11 Jul. 2012
Bearbeitet: Thomas
am 11 Jul. 2012
You need to define elev and h in the function you are calling initally.
you 'h' value comes from the funw function which will not get called unless h is defined in the VentRate function and the fzero needs 'h' and 'elev' to be present and scalars.
.m
function w = VentRate
h=0;
elev=2;
w = fzero(@funw,(h+elev)/2);
return
funw.m
function q = funw(t)
r=1/7;
q = quadl(@(x) sqrt(t^(2*r)-x.^(2*r)),h,t)...
-quadl (@(x) sqrt(x.^(2*r)-t^(2*r)),t,(h+2));
return
I cant currently check your function further for Mathematical errors but these functional errors should solve your problem..
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Numerical Integration and Differentiation finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!