How to find out the maximum number of occurrences of the sequences inside the cell array beginning with particular digit?

% Suppose I have a cellarray
C = {[1; 2; 3]; [2; 1; 3, 4]; [3; 1; 2]; [1; 2]}; % where any digit won't repeat in the individual cell.
% I was trying this code
for i = 1:3
    for j = 1:3
        for k = 1:3
            if(i ~= j && i ~= k && j ~= k) % to prevent repetition
            sequence_check  = [i; j; k];
            n = sum(cellfun(@(x) ~isempty(strfind(x.',sequence_check.')), C));
            t = table(i, j, k, n)
            end
        end        
    end    
end
% which gives me possible sequences (using 1,2 and 3) | number of occurrences
123 |  1
132    0
213    1
231    0
312    1
321    0
% I need to find out the maximum number of occurrences of the sequences inside the cell array beginning with 1 or 2 or 3 individually.
% Expected output: 
123 |  1
213    1
312    1

Answer 1

[Andrei Bobrov]

C = {[1; 2; 3]; [2; 1; 3; 4]; [ 4; 2; 1; 3];[3; 1; 2]; [1; 2]};

a = perms(1:3);
[~,j2] = cellfun(@(x)ismember(a,x),C,'un',0);
B = cat(3,j2{:});
n = sum(all(diff(B,1,2) == 1,2) & B(:,1,:) > 0,3);
lo = n > 0;
out = [a(lo,:),n(lo)];

[Md Shahidullah Kawsar]

Thanks

[Md Shahidullah Kawsar]

If I change the C and a = perms(1:10); the runtime is quite high. and If I write a = perms(1:20); it shows the maximum variable size allowed by the program is exceeded.