Attempted to access Pe(7); index must be a positive integer or logical.

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Can
Can am 8 Jul. 2012
I wrote this function but I get an error:
??? Attempted to access Pe(7); index must be a positive integer or logical.
Error in ==> prob3 at 56
Pe(m)=(Pe(m)+error(j))/10000;
What should I do for it?
Pe=zeros(1,11);
x=zeros(1,10000);
y=zeros(1,10000);
z=zeros(1,10000);
error=zeros(1,10000);
for q=0:0.1:1
for k=1:10000
error(k)=0;
end
for i=1:10000
if rand(1)<1/2
x(i)=0;
if rand(1)<q
y(i)=1;
if q<1/2
z(i)=1;
else
z(i)=0;
end
else
y(i)=0;
if q>1/2
z(i)=1;
else
z(i)=0;
end
end
else
x(i)=1;
if rand(1)<q
y(i)=1;
if q<1/2
z(i)=1;
else
z(i)=0;
end
else
y(i)=0;
if q>1/2
z(i)=1;
else
z(i)=0;
end
end
end
if x(i)==z(i)
error(i)=error(i)+0;
else
error(i)=error(i)+1;
end
end
m=(q./0.1)+1;
for j=1:10000
Pe(m)=(Pe(m)+error(j))/10000;
end
end
plot(Pe,q);

Antworten (1)

Richard Brown
Richard Brown am 9 Jul. 2012
Your problem is that q and hence m are floating point numbers, not integers. in this case the problem is that
m = 0.6 / 0.1 + 1
differs from 7 in the sixteenth decimal place, and hence can't be used to index. Either use
m = round(q / 0.1 + 1)
or, better, use integer indices in your loop, and compute q from them

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