Creating arrayfun with two variables
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Yuriy Yerin
am 17 Nov. 2018
Kommentiert: Yuriy Yerin
am 18 Nov. 2018
Hello.
I'd like to create cell array with results of a function S for variables q and k, which is defined in a code below.
function z=comparison_sum_integral_trapz
tic
format long
tt=-0.000689609;t=0.242731; muu=0.365908;
[m,NN]=meshgrid(0:100,-500:1:500);
y1= @(N,q,k) t*q./k.*log((-k.^2+2*k.*q-q.^2+muu+1i*(2*pi*N.*t-(2*m(1,:)+1)*pi*t))./(-k.^2-2*k.*q-...
q.^2+muu+1i*(2*pi*N.*t-(2*m(1,:)+1)*pi*t)))./(tt*pi+integral(@(a)a.*tanh((a.^2-muu)./(2*t)).*log((2*a.^2+2*a.*q+...
q.^2-2*muu-1i*2*pi*N*t)./(2*a.^2-2*a.*q+q.^2-2*muu-1i*2*pi*N*t))./q-2,0,10000,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true));
R1=@(q,k) integral(@(N)y1(N,q,k),500,10^6,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true);
R11=@(q,k) integral(@(N)y1(N,q,k),-10^6,-500,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true);
y2=@(q,k) t*q./k.*log((-k.^2+2*k.*q-q.^2+muu+1i*(2*pi*NN(:,1).*t-(2*m(1,:)+1)*pi*t))./(-k.^2-2*k.*q-...
q.^2+muu+1i*(2*pi*NN(:,1).*t-(2*m(1,:)+1)*pi*t)))./(tt*pi+integral(@(a)a.*tanh((a.^2-muu)./(2*t)).*log((2*a.^2+2*a.*q+...
q.^2-2*muu-1i*2*pi*NN(:,1).*t)./(2*a.^2-2*a.*q+q.^2-2*muu-1i*2*pi*NN(:,1).*t))./q-2,0,10000,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true));
R2=@(q,k) sum(y2(q,k));
S=@(q,k) R2(q,k)+R11(q,k)+R1(q,k)-4*sqrt(2)/pi*(1/1000)/(pi^(3/2)*sqrt(t))*q.^2;
q=0.001:1:7;
k=0.001:1:7;
out=arrayfun(S,k,q,'UniformOutput',false)
end
My problem is that I expected to get a cell array 7×7 but instead of I obtained 1×7.
out =
1×7 cell array
Columns 1 through 5
[1×101 double] [1×101 double] [1×101 double] [1×101 double] [1×101 double]
Columns 6 through 7
[1×101 double] [1×101 double]
Elapsed time is 3.165576 seconds.
I'd like to avoid an expoitation of
meshgrid
due to long time calculations (on the next step I will calculate the cell array out for larger arrays of q and k ).
What I did it wrong?
I will apreciate for any suggestions.
2 Kommentare
Rik
am 17 Nov. 2018
Your S function returns an imaginary array of 101 elements. Run the code below to see what happens for a scalar input. Your code doesn't have any comments, so I don't understand what it is doing, so I can't determine what to fix.
temp=S(q(1),k(1));
x=real(temp);y=imag(temp);
plot(x,y)
Akzeptierte Antwort
Guillaume
am 17 Nov. 2018
Bearbeitet: Guillaume
am 17 Nov. 2018
You seem to be expecting implicit expansion out of arrayfun (the way bsxfun works). arrayfun doesn't do that (and bsxfun can't create cell arrays, so you can't use that either. I'm afraid that you don't have any other choice than using meshgrid or ndgrid:
[k, q] = ndgrid(0.001:7);
out = arrayfun(S, k, q, 'UniformOutput', false)
3 Kommentare
Guillaume
am 17 Nov. 2018
Bearbeitet: Guillaume
am 17 Nov. 2018
I have no idea what you're implying. I don't see how logical operators would help in any way.
You could replace arrayfun by a double for loop. That would possibly be marginally faster, although usually the more costly part of arrayfun is the anonymous function call, which you would incur with the loop since S is already an anonymous function.
k = 0.001:7; q = 0.001:7;
out = cell(numel(k), numel(q));
for row = 1:numl(k)
for col = 1:nume(q)
out{row, col} = S(k(row), q(col));
end
end
edit: Note that I've not tried to understand what you're doing with S. The best solution would probably be to modify S so that it can work on array inputs instead of scalars.
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