Loop that names first 3 files one name and 2nd 3 files another.

Having a tough time doing something that is likely rather simple.

I have a folder with files, lets say they are named AAA.XLS, BBB.XLS, CCC.XLS.

I want to take half of the AAA.XLS files and rename them DDD.XLS. The files are stored so that there are 3AAA files in a row that will be kept AAA, followed by 3 files in a row that should be changed to DDD.

I have the code correct ( I believe) other than the for loop. I know how to loop every nTH iteration, but I want to do it in chunks so to speak with 3 on/3off.

Below is the code without the for loop

A =dir( fullfile(a, '*.xlsx'));

fileNames = { A.name };

for iFile = 1 : numel( A )

newName = fullfile(a, sprintf( '%03AAA.xlsx', iFile ) );

movefile( fullfile(a, fileNames{ iFile }), newName );

end

Answer 1

[Mark Sherstan]

If I understand your question correctly try implementing one of the two codes to solve your problem:

for i = 1:numel(A)
    if mod(i,3) == 0
        doSomething(i);
        continue
    end
    
    doSomethingElse(i);
end

for i = 1:3:numel(A)
    doSomething(i);
end

[JM]

Thanks for the help.

This code gives me 1, 4, 7, 10, etc when I am interested in getting 1,2,3,7,8,9,etc basically 3 on 3 off if that makes sense.

Appreciate any help you can offer

[Mark Sherstan]

Sorry for the confusion! Here is a working correction:

flag = true;

for ii = 1:20
     
    if flag == true
      % Put code here  
      fprintf('%0.0f\n',ii) 
    end
    
     if mod(ii,3) == 0
        flag = ~flag;
     end
    
end

Output is:

1
2
3
7
8
9
13
14
15
19
20