Using Delaunay triangulation to approximate the area
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Hi,
I try to use delaunay triangulation but it also connected the boundary point
As you an see the X shape, thats what I wanted only, not the square too.
thank you
2 Kommentare
John D'Errico
am 14 Nov. 2018
Bearbeitet: John D'Errico
am 14 Nov. 2018
Why did you need to ask this question twice? As I showed the last time you asked the question, you cannot use a Delaunay triangulation to do what you want, at least not without understanding how to code an alpha shape.
madhan ravi
am 14 Nov. 2018
please don‘t ask the same question twice , this discourages the answerers who answer the question
Antworten (1)
KSSV
am 14 Nov. 2018
xy = rand(5000,2);
k = (sqrt(sum((xy - [1 .5]).^2,2)) < 0.3) | ...
(sqrt(sum((xy - [0 .5]).^2,2)) < 0.3) | ...
(sqrt(sum((xy - [0.5 1]).^2,2)) < 0.3) | ...
(sqrt(sum((xy - [0.5 0]).^2,2)) < 0.3);
xy(k,:) = [];
x = xy(:,1) ; y = xy(:,2) ;
idx = boundary(x,y) ; % gives boundary
plot(x,y,'.r')
hold on
plot(x(idx),y(idx),'b')
A = polyarea(x(idx),y(idx))
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