Matlab to Python ( dot product and dot divide equivalents )

I am converting my matlab funtion to python. I want to rewrite this simple functions in python

function [ H ] = update_H( X , W , H )

H = H.*((W'*X)./secu_plus(W'*W*H,eps));
end

function [ W ] = update_W( X , W , H )

W = W.*((X*H')./secu_plus(W*(H*H'),eps));
end

Note: secu_plus is another function so ignore.

As you may see there are 2 kinds of multiplication * and .*, Also I have ./

so what are the equivalent forms in python [(.* ) (./ ) and (*) ]

Answer 1

[M]

Please refer to:

http://mathesaurus.sourceforge.net/matlab-numpy.html

or

https://docs.scipy.org/doc/numpy/user/numpy-for-matlab-users.html

Answer 2

[Fernando Feijoo]

I think that it's not possible a simple translation to python of the .* because the tratment of the operation is different in matlab and in Python. I hope this code in Python helps you

f=np.array([2,4])
t=np.array([1,2,3,4,5])
def funMatLabMultip(f,t):
    """create an n x m array from 2 vectors of size n and m.
    Resulting rows are the multiplication of each element of the first vector for all the elements of the second vector
    f=np.array([2,4])
    t=np.array([1,2,3,4,5])
    [[ 2  4  6  8 10]
     [ 4  8 12 16 20]]

    """
    if t.size==t.shape[0]:
        k=f[0]*t
        for i in f[1:]:
            j=i*t
            k=np.vstack((k,j))
    else:
        raise Exception('arrays should 1D arrays')
    return k
k=funMatLabMultip(f,t)
print(k)