find the number of occurances

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johnson saldanha
johnson saldanha am 13 Nov. 2018
Kommentiert: johnson saldanha am 13 Nov. 2018
my matrix is x=[ 1 1 1 3 3 4 4 4 6 7]
i want the output as y=[ 3 2 3 1 1]
i want to find how many times a particular value is occuring

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Stephan
Stephan am 13 Nov. 2018
Bearbeitet: Stephan am 13 Nov. 2018
y=sum(x(:)==unique(x))
Since 3 is occuring 2 times, the correct result is:
y=[3 2 3 1 1]
Best regards
Stephan
  6 Kommentare
Stephan
Stephan am 13 Nov. 2018
if you dont get it to work with this, use madhans code below.
johnson saldanha
johnson saldanha am 13 Nov. 2018
yeah i tried that it works. thank you

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madhan ravi
madhan ravi am 13 Nov. 2018
x=[ 1 1 1 3 3 4 4 4 6 7]
u = unique(x) %unique numbers
y=histc(x,u) %occurences
bonus = [u; y]' %relation between them
  2 Kommentare
johnson saldanha
johnson saldanha am 13 Nov. 2018
thanks.
madhan ravi
madhan ravi am 13 Nov. 2018
Anytime :)

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