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How to solve INDEX OUT OF BOUNDS ERROR? Please help me. Stuck in this for the past 10 days.

1 Ansicht (letzte 30 Tage)
eltn=30;
%%(b)Element Connectivity Table
count = 0 ;
conn = zeros([],3) ;
for i=1:30
for j=1:27
count = count+1 ;
conn(count,:) =[j,j+1,j+2]
end
end
%Here the Code for Assembling (OR) Global Mass Matrix
%x(i,j)=Kte_matrix(i,j); %DOUBT +=
for i=1:27
for j=1:27
MG_matrix(conn(eltn,i) - 1,conn(eltn,j) - 1)= Mte_matrix(i,j); (ERROR HERE)
end
end
How to convert conn matrix in this range??
Attempted to access conn(30,4); index out of bounds because size(conn)=[810,3].
Error in practisee2 (line 558) MG_matrix(conn(eltn,i) - 1,conn(eltn,j) - 1)= Mte_matrix(i,j);
  11 Kommentare
Walter Roberson
Walter Roberson am 12 Nov. 2018
That is quite different initialisation than what you had before.
Virajan Verma
Virajan Verma am 13 Nov. 2018
That conn matrix is showing index out of bounds error as it has only 3 columns and for i>3, it has no elements to show. That is why i changed the initialization.

Antworten (1)

KSSV
KSSV am 12 Nov. 2018
Check the function assemble in the link. This will help you.
  8 Kommentare
Virajan Verma
Virajan Verma am 13 Nov. 2018
The value of conn(eltn,j) for j=1 should be 59. How can it be zero??
Stephen23
Stephen23 am 13 Nov. 2018
Bearbeitet: Stephen23 am 13 Nov. 2018
"The value of conn(eltn,j) for j=1 should be 59. How can it be zero??"
Who said that j is equal to one when that error occurs? I don't see anything in your code that means that j equals one when that error occurs. Try looking at the value of j after the error has occured, and you might just learn something about your code.

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