How to remove a bracketed number from a cell array while leaving the number in front of it alone
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Robert Garneau
am 11 Nov. 2018
Kommentiert: Robert Garneau
am 11 Nov. 2018
Hi, I have a cell array called "mycellarray" with the following types of strings in it: 24[13]
The [13] in this case is a reference to a footnote and I want to remove the [13] and just have the number 24 left. How do I use a regular expression to remove "[13]" or any footnote i.e. [3] from the number.
Example of the contents of the cell array
13.4[5]
24[11]
56.99[23]
22[4]
I want to remove all the bracketed values along with the number inside the brackets and just have the double number in front kept in the cell array Thank you for your help.. Bob
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madhan ravi
am 11 Nov. 2018
Bearbeitet: madhan ravi
am 11 Nov. 2018
mycellarray={'24[13]'}
regexprep(mycellarray, '\[(.*?)\]', '$1') %edited after sir Walter's comment
or
A='13.4[5] 24[11] 56.99[23] 22[4]'
A(A=='[') = [];
% Remove any and all right brackets.
A(A==']') = []
2 Kommentare
Walter Roberson
am 11 Nov. 2018
'\[(.*)\]' selects too much if there can be multiple matches in one string. '\[(.*?)\]' would be better.
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